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(MED. SWING ♩=80 )
17
Jazz Piano · Parker's 12-Bar Form
Bird Blues
Major blues with descending chromatic ii-V chains, twelve keys
Play exercise
Take a 12-bar major blues form. Replace bars 5–8 — the
middle third — with a chain of descending chromatic ii-Vs
that each lead into the next without ever landing on a tonic.
That's the harmonic trick at the heart of Blues for Alice
and Charlie Parker's most intricate bebop blues vocabulary.
The form has more chords (often two per bar) than the standard
blues, but the underlying contour is the same: I → IV → cadence
→ I. What's different is the path : instead of the
simple I7-IV7-V7 of the regular blues, Bird's blues threads a
sequence of secondary-dominant ii-Vs that descend by half step
through bars 5–8 before the standard ii-V-I lands the form back
home in bars 9–11.
Bars 5–8 Chromatic ii-V chain — each ii-V leads to the next, not its target.
Heads Blues for Alice, Laird Baird.
Jump to
C F B♭ E♭ A♭ D♭ F♯ B E A D G
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7
The Daily Drill
Bird's twelve bars
5 min Play one key very slowly. Speak each chord aloud as you play. Notice that bars 2-4 form a ii-V chain that lands on the IV at bar 5 — and then bars 6-8 form three more ii-V chains that DON'T land on their targets, instead chaining chromatically down to bar 9's ii. 10 min Cycle three keys, half tempo. The dense chord changes make this much harder than a standard blues. Don't worry about voice leading at first — get the changes under your hands. 4 min Play the head of Blues for Alice over the changes (transposed to a familiar key). The melody is built from ii-V cells that match each bar's chord pair. Hearing the melody clarifies the harmonic logic. 3 min Compare to the regular 12-bar blues. Same starting and ending bars; the middle four bars are where Bird's blues diverges. The contrast shows you exactly what's added. Why descending ii-V chains? Each ii-V in bars 5-8 is a secondary ii-V — a ii-V cell that resolves down a half step to the next ii-V, not down a fifth to its expected tonic. Mathematically: Fm7-B♭7 "should" resolve to E♭, but instead it moves to Em7-A7 (a half step down from F-B♭). Em7-A7 should resolve to D, but moves to E♭m7-A♭7. E♭m7-A♭7 should resolve to D♭, but lands on bar 9's Dm7 (the standard ii of C). The unresolved cadences create harmonic motion without harmonic conclusion — perfect for the speed and density of bebop heads. Parker built much of his fastest vocabulary on this device.
Twelve bars, twenty-odd chords, the densest blues in the canon. Half the Parker heads ride this form.